Q)A circle is inscribed in the quadilateral ABCD. Given that AB = 27cm, BC=38m, DC= 25cm and AD is perpendicular to DC. Find the maximum limit of radius and the area of the circle
a)10cm,226cm^2 b) 14cm,616cm^2 c)14cm,216cm^2 d)28cm,616cm^2
e) none of these
Soln : Since OP=OS (radii) and PD=PS(tangents) and angle D= S=P=90 , hence OPDS is a square , i determined AD by foll. method
AD=AP+PD
= 27-TB+PD (since AP= AT as both are tangents and AT= 27-TB)
= 27-(38-SC)+PD
= 27-(38-SC)+(25-SC) (since PD=SD and SD= 25-SC)
AD = 14cm
and as from fig. AD= AP+PD , PD has to be smaller than 14cm under any condition and PD= OS radius of the circle , therefore the radius of the circle will definitely be less than 14cm but Arun Sharma is saying answer as option(d) radius = 28cm which is not possible .
a)10cm,226cm^2 b) 14cm,616cm^2 c)14cm,216cm^2 d)28cm,616cm^2
e) none of these
Soln : Since OP=OS (radii) and PD=PS(tangents) and angle D= S=P=90 , hence OPDS is a square , i determined AD by foll. method
AD=AP+PD
= 27-TB+PD (since AP= AT as both are tangents and AT= 27-TB)
= 27-(38-SC)+PD
= 27-(38-SC)+(25-SC) (since PD=SD and SD= 25-SC)
AD = 14cm
and as from fig. AD= AP+PD , PD has to be smaller than 14cm under any condition and PD= OS radius of the circle , therefore the radius of the circle will definitely be less than 14cm but Arun Sharma is saying answer as option(d) radius = 28cm which is not possible .
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